Question

In the given figure, AB is the diameter of a circle with O and and AT is a tangent. If ∠ AOQ = 58 o , then
the value of ∠ ATQ is -----

Answer 1

Answer:

Step-by-step explanation:

Angle ABQ=1/2 angle AOQ

=1/2*58

=29

Angle A =90(AT is a tangent)

angle BAT+angle ABT +angle ATQ=180(angle sum  

property of triangle.)  

90+29+angle ATQ= 180

angle ATQ=180-119

angle ATQ=61