In the given figure , AB parallel to. CD and angle EAB=50° . If angle ECD= 60° ,then find angle AEB
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AEB=70° ok I think it will help
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ECD=60°
Then EBA=60° ( ALTERNATE INTERIOR ANGLE )
IN ΔAEB
EAB+EBA+AEB=180° (ANGLE SUM PROPERTY)
50°+60°+AEB=180°
110°+AEB=180°
AEB=180°-110°
AEB=70°
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Then EBA=60° ( ALTERNATE INTERIOR ANGLE )
IN ΔAEB
EAB+EBA+AEB=180° (ANGLE SUM PROPERTY)
50°+60°+AEB=180°
110°+AEB=180°
AEB=180°-110°
AEB=70°
HOPE YOU LIKE THE ANSWER!!!
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