Math, asked by mauryarajkumar309, 2 months ago

In the given figure AB parallel to CD . find the values of angle X , y and Z .​

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Answered by guptaarinku
3

Answer:

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Answered by Anonymous
0

Step-by-step explanation:

ANSWER

ANSWER∠AEP+∠PEC+∠BEC=180∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘ =55∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘ =55∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘ =55∘ ∠CEB+∠ECD=180∘

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘ =55∘ ∠CEB+∠ECD=180∘ (Angles made on same side of parallel lines )

ANSWER∠AEP+∠PEC+∠BEC=180∘ (Supplementary angles)x∘+70∘ +x∘ =180∘ 2x∘ =180∘−70∘ =110∘ x=2110∘ =55∘ ∠CEB+∠ECD=180∘ (Angles made on same side of parallel lines )x+z=180∘

55∘+z=180∘

55∘+z=180∘

55∘+z=180∘ z=180∘−55 ∘ =125∘

55∘+z=180∘ z=180∘−55 ∘ =125∘

55∘+z=180∘ z=180∘−55 ∘ =125∘ ∠APE+∠PEA+∠PAE=180∘

55∘+z=180∘ z=180∘−55 ∘ =125∘ ∠APE+∠PEA+∠PAE=180∘

55∘+z=180∘ z=180∘−55 ∘ =125∘ ∠APE+∠PEA+∠PAE=180∘ y+x+90∘ =180∘

y+55∘+90∘ =180∘

y +145°=180°

y=150°/180°

y=35°

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