Question

In the given figure AB parallel to DE, angle BAC=35° and CDE=53° find angle DCE​

Answer 1

Answer:

$answer$

DEC=92°

DCE=EAB ( Alternative angle as ABIIDE and AE is transversal)

In ∆DCE, We have

DCE+CED+ CED=180°

DCE= 180°-88°=92°

$angle \: dce = 92$

Angle DCE=92°

Answer 2

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