Question

Ten year ago ,father was 12 times as old as his son 10 years hence, he will be twice as old as his son will be. Find their present age.




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Answer 1

Answer:

Let the present age of father =x years. And the present age of his son =y years. Therefore, put y=12 in equation (1). Therefore, the present age of the father is x = 34 years and the present age of y = 12 years.

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Answer 2

Explanation:

Let the present age of father =x years.

And the present age of his son =y years.

Therefore, According to first condition: -

x−10=12(y−10)

⇒x−10=12y−120

⇒x−12y=−120+10

⇒x−12y=−110 ….. (1)

Therefore, According to second condition: -

x+10=2(y+10)

⇒x+10=2y+20

⇒x−2y=20−10

⇒x−2y=10 ….. (2)

Therefore, subtracting equation (2) from (1)

(x−12y=−110) - (x−2y=10)

On subtracting, we will get

⇒−10y=−120

⇒y=−120−10

⇒y=12

Therefore, put y=12 in equation (1).

x−12y=−110

⇒x−12(12)=−110

⇒x−144=−110

⇒x=−110+144

⇒x=34

Therefore, the present age of the father is x = 34 years and the present age of y = 12 years.

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