In the given figure ABC is a triangle If AD = 3.6 cm. AB = 10 cm. AE = 1.8cm
length of AC to make DE||BC is
A] 10 cm
B] 7.2 cm
C] 20 cm
D] 5 cm
Answers
In the given figure ABC is a triangle. AD = 3.6 cm. AB = 10 cm. AE = 1.8cm. The length of AC to make DE||BC is
Consider the attached figure while going through the following steps:
Given,
AD = 3.6 cm
AB = 10 cm
AE = 1.8 cm
Thales theorem states that, "If a line is drawn parallel to one side of a triangle intersecting the remaining sides, then it divides the 2 sides in the same ratio."
Assuming DE||BC and using the Thales theorem, we have,
AD / BD = AE / CE
AD / (AB - AD) = AE / CE
3.6 / (10 - 3.6) = 1.8 / CE
3.6 / 6.4 = 1.8 / CE
1 /2 = 1.8 / CE
CE = 2 × 1.8 = 3.6 cm
Now consider,
AC = AE + CE
= 1.8 + 3.6
∴ AC = 5.4 cm
![](https://hi-static.z-dn.net/files/d32/325319576060f22597defe1ae64cbe31.png)
Answer:
d) 5cm
Step-by-step explanation:
AB=AD+DB
10=3.6+DB
10-3.6=DB
6.4=DB
According to Thales (bpt) theorem
AD/DB=AE/EC
3.6/6.4=1.8/EC(cross multiply)
11.52=3.6EC
11.52/3.6=EC
3.2=EC
AC =AE/EC
1.8+3.2
5.0
that is nothing but 5