in the given figure ABC is an isosceles triangle with ab is equal to AC if angle a is equals to 50 degree find the values of X and y
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ans is x=y=115°
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Answer:
angle abc= angle acb= (180-50)/2
=65
angle x=angle y=180-65= 115
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Step-by-step explanation:
In ∆ABC, we have,
AB = AC
=> angle ACB = angle ABC
=> angle ACB = 50° (since, angle ABC = 50°)
Therefore,
angle BAC = 180° - (angle ABC + angle ACB)
=> angle BAC = 180° - (50° + 50° ) = 80°
Now,
Since angle BAC and angle BDC are angles in the same segment.
Therefore,
angle BDC = angle BAC
=> angle BDC = 80°
Now,
BDCE is a cyclic quadrilateral.
Therefore,
angle BDC + angle BEC = 180°
=> 80° + angle BEC = 180°
=> angle BEC = 100°
Hence,
⏩angle BDC = 80° and angle BEC = 100°
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