Question

A force of 20 N acts on a wheeled log of 25 kg initially at rest. How long does the force to
displace the log through 1 hectometer and what is its velocity then?
​

Answer 1

Answer:

Coefficient of static friction μ

s

=0.3

static friction force

f

s

≤0.3×10×30

f

s

≤90N

this means that mass will not move until the pseudo force overcomes the static friction

to move the block pseudo force must be greater than 90 N

lets calculate the Pseudo force

F

p

=−ma

=30×1.8=54N

F

p

<f

s

max

Friction force is self adjustable

friction force = pseudo force = 54 N

opposite to pseudo force means in the direction of motion (due east)

Explanation:

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