A force of 20 N acts on a wheeled log of 25 kg initially at rest. How long does the force to
displace the log through 1 hectometer and what is its velocity then?
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Answer:
Coefficient of static friction μ
s
=0.3
static friction force
f
s
≤0.3×10×30
f
s
≤90N
this means that mass will not move until the pseudo force overcomes the static friction
to move the block pseudo force must be greater than 90 N
lets calculate the Pseudo force
F
p
=−ma
=30×1.8=54N
F
p
<f
s
max
Friction force is self adjustable
friction force = pseudo force = 54 N
opposite to pseudo force means in the direction of motion (due east)
Explanation:
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