In the given figure, ABCD and DMNO are two
squares. Prove that Triangle DMC is congruent to TriangleDOA.
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Answer:
ΔOAB is equilateral triangle then
ln ΔAOD and ΔBOC
AD=BC (sides of the square)
∠DAO=∠CBD=30
0
(90
0
−angleofequilateralΔ(60
0
))
AO=OB (sides of equilateral of triangle)
ΔAOD≅ΔBOC (SAS criterion)
then OD=OC
So ΔCOD is an isosceles triangle
Step-by-step explanation:
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