Question

In the given figure, ABCD and DMNO are two
squares. Prove that Triangle DMC is congruent to TriangleDOA.

Answer 1

Answer:

ΔOAB is equilateral triangle then

ln ΔAOD and ΔBOC

AD=BC (sides of the square)

∠DAO=∠CBD=30  

0

 (90  

0

−angleofequilateralΔ(60  

0

))

AO=OB (sides of equilateral of triangle)

ΔAOD≅ΔBOC (SAS criterion)

then OD=OC

So ΔCOD is an isosceles triangle

Step-by-step explanation: