Question

in the given figure abcd in which angle dab 90 degree ab =12 and bcd is equilateral triangle on diagonal bd measuring 20cm find the area of quadrilateral ​

Answer 1

Answer:

from the above figure

triangle ABD is a right angled triangle

by Pythagoras theorem

DB=AD+AB

20=AD+12

20-12=AD

8=AD

triangle DBC is an equilateral triangle

so, BC=DC=DB=20cm

Area of quadrilateral=area of triangle ADB+area of triangle DBC

area of quadrilateral= (1/2)base × height +( a^2(√3)/4)

=(1/2)12×8+((√3)/4)(20)^2

=48+173.21

=221.21cm^2ans

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