In the given figure ABCD in which BC= 25 cm and AO= 24 cm Find the sum of the length of the diagonal
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Diagonals of a rhombus are perpendicular to each other.In triangle AOB, we have:AO = 24 cmAB = 25 cmSo, by Pythagoras theorem, we have:BO = square root [(25)2- (24)2] = 7 cmAlso, the diagonals of a rhombus bisect each other.So, AC = 2AO = 48 cmand BD = 2BO = 14 cmThus, sum of lengths of diagonals = 48 cm + 14 cm = 62 cm
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62 cm
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