in the given figure abcd is a cyclic quadrilateral with a center o and diameter ad. if bcd=130°.find giving reasons
∠dab, ∠adb, ∠aeb
Answers
GIVEN:::::::
ABCD IS A CYCLIC QUADRILATERAL
ANGLE BCD = 130 DEGREE
TO FIND :::::::
THE ABOVE GIVEN ANGLES
FORMULA USED :::::
SUM OF OPPOSITE ANGLES OF A CYCLIC QUAD.
HOW TO FIND ::::"
GIVEN ANGLE BCD = 130
THEN,
ANGLE DAB = 180 - BCD = 180 - 130 = 50
( SUM OF OPPOSITE ANGLES OF A CYCLIC QUADRILATERAL IS 180)
NOW,
ANGLE ABD = 90 DEGREE
(ANGLE SUBTENDED BY THE DIAMETER ON THE CIRCLE IS 90)
THEN,
ANGLE ADB = 180-(50 + 90)
ADB = 180 - 140 = 40 DEGREE
(ANGLE SUM PROPERTY)
AGAIN,
ANGLE BDA = ANGLE BEA
(ANGLES SUBTENDED BY THE SAME CHORD ON THE CIRCLE ARE EQUAL)
SO,
ANGLE AEB = 40 DEGREE
HOPE THIS HELPS YOU......❤...PLZ MARK AS THE BRAINLIEST........
Answer:
ABCD is a cyclic quadrilateral, thus:
/_C + /_A = 180° [Sum of opposite angles of a cyclic quadrilateral is 180°]
=> /_A = 180 - 130
=> /_A = 50°
/_BDA = /_BEA [Angles on the circle by the same chord]
In triangle BDA:
/_B + /_BDA + /_A = 180° [Angle Sum Property]
=> /_BDA = 180 - 90 - 50
=> /_BDA = 40°
Thus: