Question

in the given figure .ABCD is a parallelogram and AB ||PQ prove MR||BC

Answer 1

Answer:

pls attach the figure as we dont know what are MR and PQ

Explanation:

Answer 2

Answer:

OC || SR From ∆OPS and OAB, PS||AB ∠POS = ∠AOB [common angle] ∠OSP = ∠OBA [corresponding angles] ∆OPS ∼ ∆OAB [by AAA similarity criteria] Then, Using basic proportionality theorem, We get, PS/AB = OS/OB …(i) From ∆CQR and ∆CAB, QR || PS || AB ∠QCR = ∠ACB [common angle] ∠CRQ = ∠CBA [corresponding angles] ∆CQR ∼ ∆CAB Then, by basic proportionality theorem SR || OC [By converse of basic proportionality theorem]