Question

in the given figure ABCD is a parallelogram and AP and CQ are perpendiculars from vertices A and C on diagonal BD . show that 1) triangle APB =~ CQD 2) AP = CQ​

Answer 1

In triangle APB and QCD

angle APB =angle CQD (each 90°)

AB=DC(opposite sides are equal)

angle ABP=angle QPC(AD//BC and BD is transversal and these angles are alternate interior angles)

triangle APB=triangleQCD (By AAS congruency)

Answer 2

Answer:

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