Question

in the given figure ABCD is a parallelogram and BC is a triangle find the area of the quadrilateral ABED​

Answer 1

zGiven ABCD is parallelogram.

Let the diagonal BD divides parallelogram ABCD into 2 triangles.

i.e., Δ ABD; Δ BCD

Area of ABD+ Area of BCD

=Area of ABCD

∵ ABD=BCD

∴2(Area of BCD)= Area of ABCD ……….(1)

'E' is M.P of BC, so DE divides Δ BCD into 2 equal triangles

i.e., ΔBED & Δ DEC

Area of ΔBCD= Area of ΔBED+ Area of Δ DEC.

Area of ΔBCD=2(Area of ΔDEC)

By (1)

2[2(Area of DEC)]= Area of parallelogram ABCD

4(Area of DEC)=Area of ABCD

∴ Area of ΔDEC=

4

1

(Area of parallelogram ABCD).

Answer 2

Answer:

multiply 26×18 and then divide the answer with 10= ANSWER