Question

When the pressure of 2 L of Oxygen is doubled and its temperature is also doubled from 300 K to 600 K. the
final volume of the gas is
a) 4L
b) 20 L
c) 40 L
d) 2 L​

Answer 1

a is correct answer

Explanation:

300-600= -300k

300+2L-1

=3+2-1

=4L

Answer 2

Answer:

$\bigstar{\bold{Option\:D:2\:L}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Temperature (T₁) = 300 K
• Temperature (T₂) = 600 K
• Volume  (V₁) = 2 L
• Pressure of gas is doubled

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Volume (V₂)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ We know that by ideal gas equation,

  PV = n R T

→ Here n ( number of moles ) and R ( gas constant) are constant

→ Hence we get,

  $\dfrac{P_1V_1}{T_1} =\dfrac{P_2V_2}{T_2}$

→ By given we know that

  P₂ = 2 P₁

→ Substituting the datas we get,

   $\dfrac{P_1\times 2}{300}=\dfrac{2\:P_1\times V_2}{600}$

→ Cancelling P₁  and 2 on both sides

   $\dfrac{1}{300} =\dfrac{V_2}{600}$

→ Cross multiplying,

   300 V₂ = 600

           V₂ = 600/300

           V₂ = 2 L

$\boxed{\bold{Final\:volume=2\:L}}$

→ Hence volume of the gas is constant and does not change

→ Hence option d is correct

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ Charles's law state that volume is directly proportinal to temperature when pressure is kept constant.

  $V\propto T (Pressure\:constant)$

→ Boyle's law state that volume of a gas is inversely proportional to pressure when temperature is kept constant.

  $V\propto \dfrac{1}{P} (Temperature\:constant)$

→ Gay - Lussac's law state that the pressure is directly proportional to temperature when volume is kept constant.

 $P\propto T (Volume\:constant)$