Question

In the given figure, ABCD is a parallelogram and X and Y are the midpoints of BC and AD. If BY and DX intersect the diagonal AC at the points P and Q, Prove that AP=PQ=QC.

I will mark as brainliest answer.

Answer 1

hi...


WE ARE GIVEN Y IS MID POINT..

IN ADQ,

Y IS MID POINT OF AD....

SO, P IS ALSO MID POINT OF AQ....(theorem)

$\bold{AP = PQ}$

IN CBP,
X IS MID POINT OF CB..
Q IS ALSO MID POINT OF CP.....

$\bold{CQ = PQ}$
so,

AP = PQ = CQ



$\bold{ \huge{thank \: u}}$