Question

In the given figure, ABCD is a parallelogram, angle ADE =50°and angle ACE = angle BED =90°.The value of angle EAC +angle ABC -2 angle DAC is

Answer 1

Plzz give the picture of the figure. So that anyone can answer.

Answer 2

   

Here,

∠BED = 90° ∴ ∠AEC = 45°

Then ∠EAC = 45° , ∠EAB = 45°

∠ABC = 45°

∠ADE = 50° ,  Then ∠DAC = 40°

∠EAC+∠ABC-2.∠DAC =  45° +45°-2×40°

                                      = 90°-80° = 10°