Question

In the given figure, ABCD is a parallelogram in which
angle BDC = 45° and angle BAD = 75°. Then find the measure of
angle CBD and angle ADB.​

Answer 1

∠ BDC = ∠ DBA = 45∘ (Alternate interior angles)

∠ ADB = 180∘ - (75∘ + 45∘) = 60∘

∠ ADB = ∠ DBC = 60∘ (Alternate interior angles)