Math, asked by srirangaraja25, 1 month ago

In the given figure, ABCD is a parallelogram in which ∠BDC = 45° and ∠BAD = 75°. Then, ∠CBD =?

Answers

Answered by foziakhan12

4

Answer:

BDC=DBA=45° ( alternate interior angles)

ADB=180°-(75°+45°)=60°

ADB=DBC=60° ( alternate interior angles)

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