Math, asked by riyashinde25, 2 months ago



मी समद्विभुज
त्रिकोण आहे. माझा
पाया एकरूप
बाजूंच्या दुपटीपेक्षा 3
ने जास्त आहे. माझी
परिमिती 35 सेमी
आहे,तर माझ्या
पायाची लांबी किती?

Answers

Answered by RameshChandraJoshi
1

Answer:

please give question in hindi or english language.

Answered by amitnrw
2

Given : An isosceles triangle.  

base is 3 cm more than  congruent sides.  

perimeter is 35 cm.

To Find :   the length of my base.

Solution:

congruent sides.    =   X  cm

Base = Y cm

base is 3 cm more than twice congruent sides.  

=> Y = X + 3

Perimeter  = X + X  + Y

=> 2X + y  = 35

=> 2X + X + 3 = 35

=> 3X  =  32

=> X  = 32/3  

Y = 32/3 + 3  =  41/3

Base = 41/3  cm

if use what given in question :

Then  base is 3 cm more than twice congruent sides.  

Y = 2X  + 3

=> 2X + 2X + 3 = 35

=> X = 8  and Y = 19

but such triangle is not possible as

19 > 8 + 8

and for a triangle sum of any two sides is greater than third side

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