Question

In the given figure , ABCD is a parallelogram, prove that triangle ABC congruent to triangle CDA

Answer 1

Answer:

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Answer 2

∆ ABC and ∆ CDA are Congurent, Proved

Step-by-step explanation:

In ∆ ABC and ∆ CDA

Angle B = Angle D (Angle)

( Opposite Angles of Parallelogram are equal )

AC = AC ( Common Side of Both Triangles ) (Side)

Now

As

AB // CD

And

AC is Transversal

Angle BAC = Angle ACD ( Alternate Angles are equal ) (Angle)

Here, We can see that Axiom A.S.A. Satisfied

So, ∆ ABC and ∆ CDA are Congurent

Hence Proved