In the given figure, ABCD is a parallelogram. Side DC is produced to E and AE and BE are drawn. AE intersects BC at F and DF is joined. Prove that ar(AP-m / ar(ABEF)
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Answer:
AD=6.66cm.
Step-by-step explanation:
Given,
In parallelogram ABCD, we have given AB=10cm, AE=8cm, and CF=12cm.
see this attachment figure.
⇒ AB=DC=10cm [Opposite sides of parallelogram are equal]
⇒ Lets find out area of parallelogram with height AE and base DC.
⇒ Area of parallelogram ABCD=b×h
⇒ Area of parallelogram ABCD=DC×AE
⇒ 10×8
∴ Area of parallelogram ABCD=80cm²--- equ.( 1 )
⇒ Now, to find area of parallelogram let CF be the height and AD will be base.
⇒ Area of parallelogram ABCD=CF×AD
⇒ 80=12×AD [From ( 1 )]
⇒ AD= 80/12
∴ AD=6.66cm.
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