Math, asked by rinkigupta738, 11 months ago

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CB​

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Answered by samridhraj20
1

Answer:

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CB

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)AC IS A COMMON SIDE

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)AC IS A COMMON SIDEangle BAC= angle ACD

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)AC IS A COMMON SIDEangle BAC= angle ACDTRIANGLE DCA congruence Triangle BAC BY SIDE ANGLE SIDE

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)AC IS A COMMON SIDEangle BAC= angle ACDTRIANGLE DCA congruence Triangle BAC BY SIDE ANGLE SIDECD=CB BY C.P.C.T

Answered by Anonymous
26

Answer:

Answer:

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CB

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)AC IS A COMMON SIDE

in the given figure ABCD is a quadrilateral and AC is a diagonal prove that triangle ABC=~ triangle CD||CBIn triangle ABC and TRIANGLE ACD,DC=AB(GIVEN)AC IS A COMMON SIDEangle BAC= angle ACDTRIANGLE DCA congruence Triangle BAC BY SIDE ANGLE SIDECD=CB BY C.P.C.T

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