Question

In the given figure ABCD is a rectangle prove that triangle ABC is congruent to triangle CDF​

Answer 1

Answer:

question is not given properly ABC is not a triangle. if the question would be triangle ABE and then it could be possible.

Step-by-step explanation:

if it would be triangle ABE then

DF=BE

FC=AE

angle f= angle e=90°

Hope it will help mark as brainlist.

Answer 2

Please mark as brainlist dear

Δ ABE ≅ Δ CDF In the given figure abcd is a rectangle

Step-by-step explanation:

ABCD is a rectangle

hence AB = CD  

∠DAB = 90°  & ∠ADC = 90°

in ΔOAD

∠DAE = ∠ODA + ∠AOD  ( Exterior angle = Sum of opposite two angles)

=> ∠DAB + ∠BAE = ∠ODA + ∠AOD

=> 90° + ∠BAE = ∠ODA + 90°

=>  ∠BAE = ∠ODA

now in Δ EAB  &  ΔODA

∠BEA = ∠AOD = 90°

∠BAE = ∠ODA

=> Δ EAB  ≈  ΔODA

Similarly we can show that

Δ FCD  ≈  ΔODA

Δ EAB  ≈  ΔODA & Δ FCD  ≈  ΔODA

=> Δ EAB  ≈ Δ FCD

AB = CD

hence Δ EAB  ≅ Δ FCD

=>  Δ ABE  ≅ Δ CDF