Math, asked by prayashisaikia87, 10 months ago

In the given figure,ABCD is a rhombus and angle ACB = 45°. Find angle ADC.

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Answered by bhargavaram983

3

In the diagram, we can see that BC is parallel to the side AD.

If we consider, AC as the transversal side then the angles ACB = CAD = 45

And also, for the same transversal conditions we get BAC = ACD.

In the triangle ADC, we have A and C , and thus we can find out D.

∵ A +C + D = 180

HOPE THIS ANSWER HELPS YOU.

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