Question

in the given figure,ABCD is a rhombus in which BC=25cm and AO=24cm.find the sum of the length of its diagonal​

Answer 1

Answer:

THE SUM OF THE LENGTH OF THE DIAGONAL OF A RHOMBUS IS 62cm.

Step-by-step explanation:

Diagonals of a Rhombus is perpendicular to each other.

In triangle AOB we have:-

AO = 24cm

AB = 25cm

So by Phythagoras Theorem we have...

BO= √[(25)²-(24)²]

= 7cm

Also the Diagonals of a Rhombus bisect each other.

So, AC = 2AO = 2×24 = 48cm

BD = 2BO = 2×7 = 14cm

Thus, Sum of the length of Diagonals = 48+14

= 62cm

Answer 2

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