Question

In the given figure, ABCD is a square. A line segment DX cuts the side BC at X and the diagonal AC at O such that ZCOD=115° and ZOXC = xº​

Answer 1

Answer:

Step-by-step explanation:

Given :In the figure ABCD is a square. A line segment DX cuts the side BC at X and the diagonal AC at O such that COD = 105 degree and OXC = x

To find :x

Since DX is a line segment, then

angle COD + angle COX = 180 degrees {Angle sum property}

=> angle COX = 180 -105 = 75 degrees..(1)

Since ABCD is a square and AC is a diagonal , therefore all the angles in a square is 90 degree each and AC bisects the angle in half. {property}

=> angle ACB {  also OCX } = 90 /2 =45 degrees...(2)

In traingle COX

=> angle OCX + angle COX  + x = 180 degree { sum of angles in a triangle is 180 degree}

=> x = 180 - (45+75) {using eq 1 and 2}

=> x = 60 degrees Answer

I guess you've missed 1 part of the question that OXC= x

                                         :)