Systems of forces are acting at the corners of a rectangular block as shown in figure. Determine the magnitude and direction of the resultant forces.
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Let R be the resultant of the given system. And ∑H and ∑V be the horizontal and vertical component of the resultant. ∑H = 25 – 20 = 5KN ...(i) ∑V = –50 – 35 = – 85KN ...(ii) R2 = ∑H2 + ∑V2 R2 = (5)2 + (-85)2 R = 85.14N Let Resultant makes an angle of with the horizontal tan θ = ∑V/∑H = -85/5 θ = – 86.63º Let resultant ‘R’ is at a perpendicular distance ‘d’ from point A, For finding the position of the resultant i.e. ‘d’, taking moment about point ‘A’., or apply varignon’s theorem R.d = 25 X 3 + 35 X 4 d = (75 + 140)/85.14 d = 2.53 m from point ARead more on Sarthaks.com - https://www.sarthaks.com/507900/system-forces-acting-corner-rectangular-block-determine-magnitude-direction-resultant
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