In the given figure, ABCD is a square of side 14 cm. Find the area of the shaded region.
(Take π = 22/7)
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Answer:
10.5 cm²
Step-by-step explanation:
PS=SR=RQ=QP= 7cm
Area of square PQRS= 7² = 49 cm²
Total area of the 4 quadrants= 4 ×22×3.5×3.5 ÷ 4×7
= 22×3.5×3.5÷7 =38.5 cm²
Area of shaded region = 49 - 38.5= 10.5 cm²
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