Question

In the given figure ABIICD find the value of x​

Answer 1

Answer:

From E, draw EF || AB || CD. EF || CD and CE is the transversal.

∴∠DCE+∠CEF=180°

[∵ Co-interior angles]

⇒x°+∠CEF=180°

⇒∠CEF=(180−x° )

Again, EF || AB and AE is the transversal.

∠BAE+∠AEF=180°

[∵ Co-interior angles]

⇒105°+∠AEC+∠CEF=180°

⇒105° +25° +(180° −x° )=180°

⇒310−x° =180 °

Hence, x=130°

Step-by-step explanation:

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