Question

in the given figure ABllCD, BCllDE then find the values of x and y (9th class)​

Answer 1

Given AB||CD, BC||DE,

3x=105°{Alternate interior angles }

x=105/3=35°

angleACB+angleBCD+angleDCE=180°

ACB+105+24=180

ACB+129=180

ACB=180-129=51°

Since, BC||DE

angle ACB= angle CED=y°

SO, y=51°

HOPE IT HELPS U......