in the given figure AC bisects ∠A and ∠C. if AD = 5 CM find AB.
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in ∆ABC and ∆ADC
angleBAC = angleDAC
angle BCA=angleDCA
side AC is common
so ∆ABC≈∆ADC
so AB=AD
AB= 5
angleBAC = angleDAC
angle BCA=angleDCA
side AC is common
so ∆ABC≈∆ADC
so AB=AD
AB= 5
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