In the given figure,ACD = 124° , ABC=36° then find BAC.
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in figure acd +abc+bac=180°
bac=180-124+36=20
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Answer:
if ACD =124°,
ABC= 36°
BAC= ?
SUM OF THE ALL ANGLES OF A TRIANGLE IS
180°
A .C .Q
ACD+ ABC+ BAC = 180°
124° +36° +BAC = 180°
160°+BAC=180°
BAC= 180°- 160°
BAC = 20°
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