In the given figure AD=2cm BD=3cm AE=3.5cm and AC=7cm ..Prove that DE parallel BC
Answers
Given:
In ΔABC, line DE intersect side AB and Side AC
AD = 2 cm, BD = 3 cm, AE = 3.5 cm, AC = 7 cm
To find:
DE parallel to BC = ?
Explanation:
According to Basic proportionality theorem if a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side
AD/DB = 2/3 -----(1)
EC = AC - AE = 7 - 3.5 = 3.5 cm
AE/EC = 3.5/3.5 = 1 -----(2)
From (1) and (2)
AD/DB ≠ AE/EC
Answer:
Therefore, DE is not parallel to BC
Knowledge booster:
- If a line is parallel to a side of a triangle, which intersect the other sides in two distinct points then the line divides those sides in equal proportion
- Basic proportionality theorem is also called Thales theorem
- Solve more to get good hold on it
Answer:
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Answer:−
Given:
In ΔABC, line DE intersect side AB and Side AC
AD = 2 cm, BD = 3 cm, AE = 3.5 cm, AC = 7 cm
To find:
DE parallel to BC = ?
Explanation:
According to Basic proportionality theorem if a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side
AD/DB = 2/3 -----(1)
EC = AC - AE = 7 - 3.5 = 3.5 cm
AE/EC = 3.5/3.5 = 1 -----(2)
From (1) and (2)
AD/DB ≠ AE/EC
Answer:
Therefore, DE is not parallel to BC
Knowledge booster:
If a line is parallel to a side of a triangle, which intersect the other sides in two distinct points then the line divides those sides in equal proportion
Basic proportionality theorem is also called Thales theorem
Solve more to get good hold on it