IN the given figure ad=7√3 then find the value of bc
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In triangle ACD ,Tan 60 =AD/DC
√3=7√3/y
y =7√3/√3
y=7
In triangleABD
Tan 30=AD/BD
1/√3=7√3/x
x=7√3×√3
x=21
BC=x+y
BC=21+7
BC = 28 units
Hope it helps
√3=7√3/y
y =7√3/√3
y=7
In triangleABD
Tan 30=AD/BD
1/√3=7√3/x
x=7√3×√3
x=21
BC=x+y
BC=21+7
BC = 28 units
Hope it helps
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