Question

In the given figure , AD = AE , BD = CE . Prove that ∆AEB is congruent to ∆ADC.

Answer 1

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Answer 2

Solutions:

We have,

AE = AD and CE = BD

=> AE + CE = AD + BD

=> AC = AB ............... (i)

Thus, in △'sAEB and ADC, we have

AE = AD ............ [Given]

∠EAB = ∠DAC .......[Common]

and, AC = AB ......... (i)

So, by SAS criterion of congruence, we obtain

△AEB ≅△ADC