Question

In the given figure, AD = BC, then show that AC = BD are equal​

Answer 1

Answer:

In △s ADB and ACB

AD=BC (Given)

AC=BD

AB=BA (Common)

∴ △ADB≅△ACB (SSS)

⇒ ∠ABD=∠CAB (cpct)

⇒ ∠ABP=∠PAB

⇒ PA=PB (Sides opp. equal angles are equal)

⇒ △PAB is isosceles.