In the given figure, AD = CD and AB = CB. Prove that:
1. triangle ABD congruent to
Triangle CBD
2. BD bisects <ABC
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GIVEN,
AD = CD
AB = CB
Prove : ΔABD≅ΔCBD
BD bisects ∠ABC.
1. prove ΔABD≅ΔCBD
AD = CD (given)
AB = CB (given)
BD = BD (common)
hence, ΔABD≅ΔCBD by SSS congruence. (side, side, side)
2. BD bisects ∠ABC.
∠ABD = ∠CBD (corresponding parts of congruent triangles - CPCT)
hence, we can say BD bisects ∠ABC
HOPE IT HELPS
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shrene1528:
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