In the given figure, AD divides ZBAC in the ratio 1:3 and AD = DB. Find
the value of x.
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AD divides ∠ BAC in the ratio 1 : 3.
So, let ∠BAD=y and ∠DAC=3y
Now,
y+3y+108=180
4y=72
y=18
Now, since AD = BD, therefore,
∠BAD=∠ABD=y=18
∠ADC=2y=36
Therefore, in △ADC,
x+36+54=180
x=90o
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