In the given figure, AD is the median ,then find ∠BCA .
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Answer:
ABC is an isosceles triangle since AB=AC. ∠B=∠C=35
∘
∠A=110
∘
(∵∠A+∠B+∠C=180
∘
)
In an isosceles triangle, median (AD) to the base BC is the angular bisector of ∠A
Hence, ∠BAD=55
∘
Answered by
10
Answer:
In the given figure,
AD is the median
∠ABC = 35 ⁰
And AB is equal to AC
Therefore ∠ABC = ∠ACB
Hence ∠ACB = 35 ⁰ (Angles opposite to equal sides are equal)
Hence proved
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