In the given figure , AD perpendicular CD and BC perpendicular CD. If AQ=BP and DP=CQ, Prove that angle DAQ=angleCBP
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DP = CQ
DP + PQ = CQ + PQ
DQ = PC
CONSIDER ∆DAQ AND ∆CBP
DQ = PC
AQ = BP
/_ ADQ = /_ BCP
BY RHS CONGRUNCE RULE,
∆DAQ = ∆CBP
/_DAQ = /_CBP
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