In the given figure, an ammeter is put to measure the current through the resistor and a voltmeter to measure the voltage across the 12 ohm resistor. Note down the reading in the ammeter and the voltmeter.
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Explanation:
The switch is open so both will be 0.
But if we close the switch:-
I=V/R = 8/25 = 0.32 A
so ammeter will show 0.32 A
Now we have to calculate the PD for 12 ohm resistor.
Since current remains same for series circuit, I=0.32 A
V=IR
so V= 0.32 x 12 = 3.84 volts
therefore voltmeter will show 3.84V
Hope my answer is correct
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