Question

In the given figure, angle A=60,CE parallel BA and angle ECD=55,then find the value of angle ACB.​

Answer 1

Answer:

R.E.F. Image.

∠A=60∘

CE || AB

∠ECD=65∘

(Interior Alternate Angle)

∠BAC=∠ACE

∠ACE=60∘

∠BCD=180∘

(linear Angle) or (linear Point)

∠ACB+∠ACE+∠ECD=180∘

∠ACB=180∘ −(60+65)

=180∘ −(125)

∠ACB=55∘

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Answer 2

Answer:

R.E.F. Image.

∠A=60∘

CE || AB

∠ECD=65∘

(Interior Alternate Angle)

∠BAC=∠ACE

∠ACE=60∘

∠BCD=180∘

(linear Angle) or (linear Point)

∠ACB+∠ACE+∠ECD=180∘

∠ACB=180∘−(60+65)

=180∘−(125)

∠ACB=55∘