In the given figure, angle AB = CD AD = BC. prove that angle BAC= ACD.
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IN TRIANGLE ABC & TRIANGLE ACD
AB=CD
AD=BC
AC=AC......COMMON SIDE
TRIANGLE ABC CONGRUENT TRIANGLE ACD
THEREFORE ANGLE BAC =ACD .... C.A.C.T
AB=CD
AD=BC
AC=AC......COMMON SIDE
TRIANGLE ABC CONGRUENT TRIANGLE ACD
THEREFORE ANGLE BAC =ACD .... C.A.C.T
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Answer:
This is a rectangle which is bisected in a diagonal way and our diagonal is l(AC). The l(AD)=l(BC), l(AB)=l(DC). So the answer will be in the following manner.
Step-by-step explanation:
According to given condition l(AD)=l(BC), l(AB)=l(DC).
Therefore the diagonal of the rectangle bisect the rectangle into equal parts The Perimeter, Area, Surface of triangle ABC and triangle ADC is equal
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