Math, asked by vivek4895, 10 months ago

In the given figure, angle AB = CD AD = BC. prove that angle BAC= ACD.

Attachments:

ruthvikrp853: Stupid people
ruthvikrp853: AB=BC
ruthvikrp853: AD=BC
ruthvikrp853: AC =AC (common)
ruthvikrp853: By SSS rule ∆ABC=∆ADC
ruthvikrp853: And angle BAC=ACD
ruthvikrp853: By CPCT

Answers

Answered by ruchi1803
20
IN TRIANGLE ABC & TRIANGLE ACD
AB=CD
AD=BC
AC=AC......COMMON SIDE
TRIANGLE ABC CONGRUENT TRIANGLE ACD
THEREFORE ANGLE BAC =ACD .... C.A.C.T

ruthvikrp853: Its CPCT
ruchi1803: no its c.a.c.t congruent angle of congruent triangle
saNuRana: Hello ruchi
Answered by sairajsah77
3

Answer:

This is a rectangle which is bisected in a diagonal way and our diagonal is l(AC). The l(AD)=l(BC), l(AB)=l(DC). So the answer will be in the following manner.

Step-by-step explanation:

According to given condition  l(AD)=l(BC), l(AB)=l(DC).

Therefore the diagonal of the rectangle bisect the rectangle into equal parts The Perimeter, Area, Surface of triangle ABC and triangle ADC is equal

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