Math, asked by amssre15683, 5 hours ago

In the given figure,angle ABC=80°,angle=ACE=70°.If AB is parallel to CE, then find the measure of angle ACB.​

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Answered by chareendo
4

Answer:

ace=bac

bac =70

70+80+acb=180

Acb=180-150

ACB=30

Step-by-step explanation:

monkey is always right

Answered by raivaishali84
7

Answer:

angle ACE= angle CAB. (alternate angle)

so in triangle BAC

angle ABC + angle ACB + angle CAB=180°

80°+ angle ACB + 70°=180°

angle ACB+150°=180°

angle ACB=180°-150°

angle ACB=30°

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