In the given figure,angle ABC=80°,angle=ACE=70°.If AB is parallel to CE, then find the measure of angle ACB.
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4
Answer:
ace=bac
bac =70
70+80+acb=180
Acb=180-150
ACB=30
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Answered by
7
Answer:
angle ACE= angle CAB. (alternate angle)
so in triangle BAC
angle ABC + angle ACB + angle CAB=180°
80°+ angle ACB + 70°=180°
angle ACB+150°=180°
angle ACB=180°-150°
angle ACB=30°
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