In the given figure angle abc =90 and BM is a median,AB =8cm and BC=6cm. then find the lenght of BM
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Solution:-
Given ∠ ABC = 90°, AB = 8 cm and BC = 6 cm
Since ABC is a right triangle, We can use the Pythagoras Theorem to get the side AC.
(AB)² + (BC)² = (AC)²
8² + 6² = (AC)²
(AC)² = 64 +36
(AC)² = 100
Ac = 10 cm
Since BM divides the side AC in two parts AM and CM.
So, we have two isosceles triangles formed which are Δ ABM and Δ BMC.
Therefore the two triangles having the common side as 5 cm.
So, the length of BM is 5 cm.
Given ∠ ABC = 90°, AB = 8 cm and BC = 6 cm
Since ABC is a right triangle, We can use the Pythagoras Theorem to get the side AC.
(AB)² + (BC)² = (AC)²
8² + 6² = (AC)²
(AC)² = 64 +36
(AC)² = 100
Ac = 10 cm
Since BM divides the side AC in two parts AM and CM.
So, we have two isosceles triangles formed which are Δ ABM and Δ BMC.
Therefore the two triangles having the common side as 5 cm.
So, the length of BM is 5 cm.
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