in the given figure angle ABC is 65 and bce is 30 dce is 35 and angle 145 show that Ab parallel ef
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Step-by-step explanation:
Given, ∠ABC = 65°.
⇒ ∠ BCD = ∠BCE + ∠DCE
= 30 + 35
= 65°
So, ∠ABC = ∠BCD.
∴ CD ║ AB. ---- (i)
⇒ ∠ECD + ∠CEF = 35 + 145
= 180°
∴ CD ║ EF ----- (ii)
From (i) & (ii), we get
AB ║ EF.
Hope it helps!
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