Question

In the given figure angle ADB = angle ACB and angle ABD= angle BAC. Prove that AD= BC.

Answer 1

→Angle ADB=Angle ACB(Given)
→Angle ABD=Angle BAC(Given)
→BA=BA(common)
==
==
HENCE,
→∆ABD=∆BAC=(AAS)
→and AD=BC (From ∆ABD=∆BAC)
Hence proved

Answer 2

hey

___________

given

<ADB =<ACB

<ABD=<BAC

to prove : AD=BC

proof :

in∆CBA and ∆DAB

<ADB=<ACB (given)

<ABD=<BAC (given)

AB=AB (common)

∆CBA congruent ∆DAB by AAS criteria

hence AD=BC by c.p.ct prooved

hope helped

________________