Math, asked by simra32247, 1 year ago

in the given figure angle AOD =100° find angle BCD if AB is diameter and BC tangent ​

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Answered by HUMSI
2
hope it helps you
all the best
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simra32247: no ur ans is incorrect..sorry
HUMSI: what's the answer then
simra32247: 40°
HUMSI: nope 50 check once
simra32247: Oh oky let me check...
simra32247: it's.50°.. sorry..
simra32247: thank u
HUMSI: no problem
Answered by angeltamang162
1

OBC=90

DOB=180-100=80

OBD+DOB+DCB+ODC=360

90+80+DCB+ODC=360

170+DCB+ODC=360

DCB+ODC=360-170=190

In triangleAOD

AO=OD (radius)

OAD=ODA(isoceles triangle)

OAD+ODA+AOD=180

2OAD+100=180(OAD=ODA)

2OAD=180-100=80

OAD=40=ODA

ODC=180-40=140

OBC+BOD+ODC+BCD=360

90+80+140+BCD=360

170+140+BCD=360

310+BCD=360

BCD=360-310=50

answer is 50

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